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#91
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Full Moon Handheld- Clark, my apologies!
Joseph Miller wrote:
Joseph Miller wrote: First I apologize for adding an "e" to your name. I don't know why I did that. Second, with a little more time to read things, I realized that I was putting words in your mouth. You never did say that the shadows at the south pole were only a result of the moon not being full. I was mislead by your making a point out the fact that the phase was not exactly full. The fundamental trap I fell into was interchanging phase angle (a technical term with a precise definition) and angle of phase- the sun-earth-moon angle. The fundamental point remains. When you took your picture the phase angle was well off zero, with a lot of it in a north-south direction. The phase angle at full moon will be effectively zero when the full moon is on the ecliptic (and an eclipse takes place), but if the fulll moon is far from the ecliptic, a significant north-south phase angle can be observed. Joe, No problem. Often people misunderstand each other in brief exchanges on usenet. The challenge is not letting it deteriorate. I do agree the apparent distance from the ecliptic plays a big role in the shadows seen near full moon, but it is in reality a little more complex. The Earth, for example is not always on the ecliptic. The ecliptic is the mean orbital plane and the Earth deviates from that plane a little due to pull from other planets that are out of the plane. The mean ecliptic is defined for some time, like J2000 is in common use. Even the moon's orbit and the moon's inclination has an effect. http://www.bado-shanai.net/Astrogati...arthsorbit.htm The full moon is defined as when the moon is 180 degrees ecliptic longitude from the sun. But yes it can be above or below the ecliptic. Thus the full moon can be less than 180 actual degrees from the sun, and that is what is expressed in the phase angle. Full moon usually is less than 180 degrees from the sun (lunar eclipses are rare). Then add another complication: where on the Earth you view the moon. That varies by about 2 degrees. So, adding the Earth's deviation from the ecliptic, the moon's ecliptic latitude, and where and when you view the moon on the Earth complicates simply using the moon's ecliptic distance for predicting/explaining the shadows. So, again, the phase angle gives the correct answer, especially when computed for your exact time and location. In the case of my lunar image, which was not at exact full moon, that angular distance from 180 degrees ecliptic longitude adds another factor in making the shadows, but that is accounted for in the phase angle. So, for you class, I suggest using your idea of the moon being out of the ecliptic as a first approximation of the effect, but then introduce phase angle and how it applies to everything we observe around us (best ignore multiple light sources to start). Then, you can predict for any situation, e.g. the view of the moon from a spacecraft, or the view of a mountain and the setting sun, what the shadows will be like. It works great for photographers too. Roger |
#92
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Full Moon Handheld- Clark, my apologies!
Roger N. Clark (change username to rnclark) wrote:
No problem. Often people misunderstand each other in brief exchanges on usenet. The challenge is not letting it deteriorate. What did you just say about my momma? |
#94
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Full Moon Handheld- can't resist pointing something out.
wrote:
(Roger N. Clark) wrote: " The dark spots are not exposed bedrock. There is lunar dust everywhere created by small meteor impacts, and is called a regolith. The dark areas (mare) are different in composition and generally are relatively younger basalt flows that erupted after the large impact basins were formed. The lighter areas are called highlands because they generally are higher. The mare basalts contain more pyroxene (a dark mineral with lots of iron, thus called mafic), and the highlands contain relatively more feldspar (a light mineral with little iron). " ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ Care to try and explain why the 'not exposed bedrock but younger basalt flows' are only located in a small part of the moon? =================================== (Roger N. Clark) wrote: " Yes, they are called crater rays. Rays are lighter in both the darker mare and the lighter highlands mainly due to the fine particle size of the smashed up rocks. " ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^ AND those fine particles would be over every inch of the moon, if it were as you say, since the moon is hit incessantly by asteroids. Instead it's only over the dark spots from where recent asteroids have hit. (as the rays show) If your theory was correct, the 'mare' spots would have been covered over a long time ago. It is not my theory; it is results from the Apollo missions and Earth-based telescopic work (using light to probe the microstructure of the lunar soil). See: http://en.wikipedia.org/wiki/Regolith http://www.meteorites.wustl.edu/luna...th_breccia.htm The mare locations predominantly on the side facing the Earth has been hypothesized as due to an asymmetry in the lunar crust thickness and eruption of the mare basalts at thinner locations in the crust. There are other explanations too, e.g. http://www.lpi.usra.edu/meetings/lpsc2000/pdf/1984.pdf Many moons and planets show hemispheric differences, even the Earth (the Pacific ocean dominates one hemisphere). Most moons are tidally locked due to asymmetries in their mass distribution. Roger |
#95
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Full Moon Handheld
"Roger N. Clark (change username to rnclark)" wrote in message ... Saguenay wrote: "Battleax" a écrit dans le message de news: ... Sure, you'll prefer this 500mm NOT handheld: http://baron.phpnet.us/50-500/crw_05...?size=1&exif=Y (a few days before)... Saguenay Very nice image. But you'll just make the troll more jealous. Roger Troll? I think that it would appear that he was quite correct from this demonstration, why call him a troll. |
#96
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Full Moon Handheld
"Roger N. Clark (change username to rnclark)" wrote in message ... Battleax wrote: "Roger N. Clark (change username to rnclark)" wrote in message ... I finally had a night with a steady atmosphere, so I tried imaging the full moon handheld at 1000 mm (real focal length): http://www.clarkvision.com/galleries...3f-8s-800.html This was done standing up with no supports and not leaning against anything. The full resolution image can be seen from the above page. Roger Over exposed, lost detail. Just another unremarkable moon shot I'm afraid. The fact that it is hand-held is completly irrelevant Wrong. Not one pixel is saturated. That fact does not make it properly exposed. See the far better exposed shot further up in the thread, much better. |
#97
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Full Moon Handheld
Pete D wrote:
http://www.clarkvision.com/galleries...3f-8s-800.html Over exposed, lost detail. Just another unremarkable moon shot I'm afraid. The fact that it is hand-held is completly irrelevant Wrong. Not one pixel is saturated. That fact does not make it properly exposed. See the far better exposed shot further up in the thread, much better. 1) there is no other full moon image further up the thread. 2) On my calibrated monitors I can see detail in the brightest parts of the image, as well as darkest, and everywhere in between. 3) The full moon appears very bright to both the unaided eye and through a telescope, and the image gives that impression, the exact effect I was trying for. Roger |
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