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#102
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Nikon D800/E $3000, cheaper than I thought
Floyd L. Davidson wrote:
Yes, exactly. Nozzle squirts are not pixels. 2880x1440 nozzle squirts in an inch for 360 pixels is... an 8x4 matrix for each pixel. Look on page 11 of the Service Manual where it shows the horizontal resolution of 2880 is for a print area of 17.39" and that it can lay down 50,029 dots of ink. With 8 colors, that is one nozzle from each color into 360 pixels per inch. Look on page 40 of the Service Manual where it shows that in the vertical direction the head spacing is 1/360", and that there are 4 pairs of nozzle rows vertically, each offset horizontally from each other by 280/720" while each pair is separated by 65/720". And vertically the nozzles in each pair of rows are 1/360" apart. It prints at 360 Pixels Per Inch. No more, and no less. This simply isn't true: it's possible to print a clearly discernible 720ppi grid (i.e. 360 cycles per inch) on an Epson 9900. I can provide a scan if you don't believe me, or you could try it yourself. Andrew. |
#103
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Nikon D800/E $3000, cheaper than I thought
nospam wrote:
In article , David Dyer-Bennet wrote: Big prints are all the rage, among those who make prints at all. no, they most definitely are not. the most popular print size is 4x6, and has been for a long time. most people don't own a printer that can go beyond 8.5x11 (or perhaps longer with roll paper). plus, with digital, most people don't print anymore, they upload to facebook or flickr or just email it. Go look in any gallery exhibition. Those prints are getting bigger. gallery prints are a tiny, tiny fraction of photography. Sure, lots of people still make 4x6 prints for their albums, that's not changing that much. actually, it is changing quite a bit. people no longer print or put into albums. instead, they upload to facebook, flickr, etc. and/or carry their photos on a smartphone or tablet. the albums are now digital. But art prints are getting much bigger. so what. most photos don't ever end up as art prints. I print few of my photos, and those I do print are mostly 6"x4". Less than 0.5% of my photos end up on walls as A3 or larger prints. But it takes me a while to decide which ones. And sometimes a neglected old photograph suddenly becomes topical and interesting. So I take most of my photographs aiming at an image quality good enough for A2 with a bit of cropping. -- Chris Malcolm |
#104
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Nikon D800/E $3000, cheaper than I thought
Floyd L. Davidson wrote:
Eric Stevens wrote: On Thu, 08 Mar 2012 16:54:53 -0900, (Floyd L. Davidson) wrote: Because when you finally understand what this is all about, it will be obvious that 2880 dots per inch when there are 8 different colored dots means simply 2880/8 is how often each color can appear. Get out your calculator and divide 2880 by 8. [...] And therefore the number of *pixels* per inch cannot be greater than 2880 dot divided by 8 nozzles... That's assuming a single print pass. No **** Sherlock. (Re-read what I've said previously.) So you do agree that with an ink coverage of 300% (very common!) any dot position can be occupied by 3 different colours.[1] (ignoring any different ink amounts of the dots) With 8 colours (k (matte or gloss) lk llk c lc m lm y) not all colours will be needed at the same place. It can be assumed that only one of the 3 blacks are used, and either the light or the normal version of cyan and magenta. Thus there are roughly only 4 colours used in any pixel, and the mixture in same parts of cyan, magenta and yellow can be replaced by black and vice versa. You can now calculate for yourself how many different dot positions you need per pixel. Your "obvious that 2880 dots per inch when there are 8 different colored dots means simply 2880/8 is how often each color can appear" is clear bull and shows you have very little idea of how the stuff works. -Wolfgang [1] Depending on the maximum repeat rate of the nozzle it may need several passes of the head to print all dot positions with one ink. |
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