Your calculations are off 1" = 1800 x 1.5" =2700 = approx 4.9 MegaPixels
"Paul J Gans" wrote in message ... rafe bustin wrote: On Tue, 08 Feb 2005 13:28:51 +0900, Stewy wrote: In article , rafe bustin wrote: On Mon, 07 Feb 2005 17:51:33 +0900, Stewy wrote: In article , Gel wrote: I have a large (1000+) amount of 35mm transparencies to scan to DVD and have been looking in Jessops ( UK ) at their brand (1800dpi) at ?100- Now, would I be better off with a Minolta at ?2-300 more? Or would the quality of the Jessops cheapie be sufficient? I will also be using the scanner for 35mm film negative scanning, does this require the better quality scanner... I bought the 1800i a couple of years back and have been very pleased with the results. Scans result in a 8 megapixel image which is quite adequate for printing. Something's wrong with your math here. 1800 dpi can't get 8 megapixels from a 35 mm frame. A 35 mm frame is approx 1.5 square inches, which would be 4.86 Mpixels at 1800 dpi. Whoops! You're right of course was thinking of 24mm x 36mm Yes, that's 35 mm film. 1.5 square inches is a very close approximation.. and makes it easy to get total pixels from dpi. Yup. I've just checked the arithmetic -- except that 1.5 inches square is a tad generous. I make it about 1.33 inches square. But never mind, the point is well made. ----- Paul J. Gans |
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