Filter ???
Hi, I need to know how many stops of light I will lose using a B+W 091 dark
red filter? Thanks,mj |
Filter ???
In article k.net, "Mike
Jenkins" wrote: Hi, I need to know how many stops of light I will lose using a B+W 091 dark red filter? Thanks,mj It's got a filter factor of about 8 (3 stops) and admits light of about 600nm on up. |
Filter ???
Mike Jenkins wrote:
Hi, I need to know how many stops of light I will lose using a B+W 091 dark red filter? 3 stops. I've also found that some B&W films might need even more exposure to get printable negs using this type of filter so I'd bracket another stop over and look at the results. -- Stacey |
Filter ???
Stacey wrote:
Hi, I need to know how many stops of light I will lose using a B+W 091 dark red filter? 3 stops. I've also found that some B&W films might need even more exposure to get printable negs using this type of filter so I'd bracket another stop over and look at the results. Depends on type of light too. In artificial light, there is proportionally more red, hence a larger part will be filtered out, which in turn means more compensation needed. In daylight, there is ... You get the picture. ;-) |
Filter ???
"Q.G. de Bakker" wrote in message ... Stacey wrote: Hi, I need to know how many stops of light I will lose using a B+W 091 dark red filter? 3 stops. I've also found that some B&W films might need even more exposure to get printable negs using this type of filter so I'd bracket another stop over and look at the results. Depends on type of light too. In artificial light, there is proportionally more red, hence a larger part will be filtered out, which in turn means more compensation needed. Oops. In daylight, there is ... You get the picture. ;-) David J. Littleboy Tokyo, Japan |
Filter ???
David J. Littleboy wrote:
Depends on type of light too. In artificial light, there is proportionally more red, hence a larger part will be filtered out, which in turn means more compensation needed. Oops. "Oops" indeed. Anyway, "You get the picture. ;-)" |
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