Useful 10% solutions
 

"Hydroquinone: To increase the print contrast add 100ml per liter of
working developer."

How does one make a 10% solution of this photo chemical?

the quote comes from,

http://www.jackspcs.com/pitone.htm

Useful 10% solutions
 

A 10% solution of anything (anything soluble anyway) starts with 10 grams of
weighed material in 100ml water (which weighs 100 grams) the ration is 1
part to 10 parts water.

--
darkroommike

wrote in message
oups.com...
"Hydroquinone: To increase the print contrast add 100ml per liter of
working developer."

How does one make a 10% solution of this photo chemical?

the quote comes from,

http://www.jackspcs.com/pitone.htm

Useful 10% solutions
 

wrote:
"Hydroquinone: To increase the print contrast add 100ml per liter of
working developer."

How does one make a 10% solution of this photo chemical?

the quote comes from,

http://www.jackspcs.com/pitone.htm


Unless you are going to use it immediately you will probably want some
sodium sulfite in this 10% solution too. Its best to start with less
than 1000 ml water and add water to make 1000 after dissolving both the
sulfite and HQ. Otherwise you may end up with slightly more than 1000
ml, and hence a slightly weaker solution. It probably wont make much of
a practical difference in this case but its a good practice to get
into. I'll let someone else suggest how much sulfite you will need.

Useful 10% solutions
 

Mike King wrote:
A 10% solution of anything (anything soluble anyway) starts with 10 grams of
weighed material in 100ml water (which weighs 100 grams) the ration is 1
part to 10 parts water.

Isn't it 10g of weighed material dissolved in enough water to make a total
of 100ml of solution?

See:

http://www.coscosci.com/lab/test_solns.htm

Dana

Useful 10% solutions
 

On Wed, 29 Mar 2006 10:18:35 -0800, "Dana H.
Myers" wrote:

Mike King wrote:
A 10% solution of anything (anything soluble anyway) starts with 10 grams of
weighed material in 100ml water (which weighs 100 grams) the ration is 1
part to 10 parts water.

Isn't it 10g of weighed material dissolved in enough water to make a total
of 100ml of solution?

See:

http://www.coscosci.com/lab/test_solns.htm

Dana


March 29, 2006, from Lloyd Erlick,

Yes, it is.

regards,
--le

Useful 10% solutions
 

Dana H. Myers wrote:

Isn't it 10g of weighed material dissolved in enough
water to make a total of 100ml of solution?


A solution is a solvent plus solute. At least in the
darkroom % solutions are used. A 10% solution will
have as 1/10 it's volume some solute. Usually the
portion of solute is in grams. Dan

Useful 10% solutions
 

wrote

A solution is a solvent plus solute. At least in the
darkroom % solutions are used. A 10% solution will
have as 1/10 it's volume some solute. Usually the
portion of solute is in grams.

Though if it is two liquids the concentration can
be by volume - Misters Walker and Daniel are 40%
alcohol by volume.

Useful 10% solutions
 

Useful 10% solutions
 

Dana H. Myers wrote:

I know what the volume of 10 grams of water is.
What's the volume of 10g of NaOH?

I think you're mixing up two different conventions.
Dana


A 10ml solution of 10% NaOH will have 1 gram
of the solute; 10% of the solutions volume. As I said
the solute's amount is usually in grams. Dan

Useful 10% solutions
 

wrote
A 10ml solution of 10% NaOH will have 1 gram
of the solute; 10% of the solutions volume.

Not 10% of the unit's volume ... usually the
volume of the solution is less than the volume
of the sum of the individual components.

A 10% by weight solution is a bit confusing ...
better to call it a .1g/ml or 100g/l solution.

Mixing mass and volume is a no-no, though for
water the two are functionally the same: 1g = 1ml.
After the solution is made up, however, the density
is normally greater than 1g/ml and the equivelance
is no longer.

Example, 10% mass(weight)/vol solution of salt water:

100 g salt \
= 1000ml salt water with a density
990 ml H20 / of 1090 g/l

(I can't remember the actual numbers for salt water
and I can't find the CRC)

To make a 10% w/v solution you put in 100 gm of stuff and
add _however much water it takes_ to make 1 liter. The
amount of water required varies with what the stuff is.

Imagine a 10% w/v solution of Styrofoam balls: all Styrofoam
and just about no water.

--
Nicholas O. Lindan, Cleveland, Ohio
Consulting Engineer: Electronics, Photonics, Informatics.
Remove blanks to reply: n o lindan at ix . netcom . com